32a^2+44a=0

Solution for 32a^2+44a=0 equation:

32a^2+44a=0

a = 32; b = 44; c = 0;
Δ = b2-4ac
Δ = 442-4·32·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-44}{2*32}=\frac{-88}{64}
=-1+3/8
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+44}{2*32}=\frac{0}{64}
=0
$